15x^2-29x+14=0

Solution for 15x^2-29x+14=0 equation:

15x^2-29x+14=0

a = 15; b = -29; c = +14;
Δ = b2-4ac
Δ = -292-4·15·14
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-1}{2*15}=\frac{28}{30}
=14/15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+1}{2*15}=\frac{30}{30}
=1
$